-16x^2+22x+108=0

Solution for -16x^2+22x+108=0 equation:

-16x^2+22x+108=0

a = -16; b = 22; c = +108;
Δ = b2-4ac
Δ = 222-4·(-16)·108
Δ = 7396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7396}=86$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-86}{2*-16}=\frac{-108}{-32}
=3+3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+86}{2*-16}=\frac{64}{-32}
=-2
$